How many milliliters of concentrated hydrochloric acid solution ( 36.0 % HCl by mass, density =1.18  g / mL ) are required to produce 10.0  L of a solution that has a pH of 2.05 ? | Numerade (2024)

`); let searchUrl = `/search/`; history.forEach((elem) => { prevsearch.find('#prevsearch-options').append(`

${elem}

`); }); } $('#search-pretype-options').empty(); $('#search-pretype-options').append(prevsearch); let prevbooks = $(false); [ {title:"Recently Opened Textbooks", books:previous_books}, {title:"Recommended Textbooks", books:recommended_books} ].forEach((book_segment) => { if (Array.isArray(book_segment.books) && book_segment.books.length>0 && nsegments<2) { nsegments+=1; prevbooks = $(`

  • ${book_segment.title}
  • `); let searchUrl = "/books/xxx/"; book_segment.books.forEach((elem) => { prevbooks.find('#prevbooks-options'+nsegments.toString()).append(`

    ${elem.title} ${ordinal(elem.edition)} ${elem.author}

    `); }); } $('#search-pretype-options').append(prevbooks); }); } function anon_pretype() { let prebooks = null; try { prebooks = JSON.parse(localStorage.getItem('PRETYPE_BOOKS_ANON')); }catch(e) {} if ('previous_books' in prebooks && 'recommended_books' in prebooks) { previous_books = prebooks.previous_books; recommended_books = prebooks.recommended_books; if (typeof PREVBOOKS !== 'undefined' && Array.isArray(PREVBOOKS)) { new_prevbooks = PREVBOOKS; previous_books.forEach(elem => { for (let i = 0; i < new_prevbooks.length; i++) { if (elem.id == new_prevbooks[i].id) { return; } } new_prevbooks.push(elem); }); new_prevbooks = new_prevbooks.slice(0,3); previous_books = new_prevbooks; } if (typeof RECBOOKS !== 'undefined' && Array.isArray(RECBOOKS)) { new_recbooks = RECBOOKS; for (let j = 0; j < new_recbooks.length; j++) { new_recbooks[j].viewed_at = new Date(); } let insert = true; for (let i=0; i < recommended_books.length; i++){ for (let j = 0; j < new_recbooks.length; j++) { if (recommended_books[i].id == new_recbooks[j].id) { insert = false; } } if (insert){ new_recbooks.push(recommended_books[i]); } } new_recbooks.sort((a,b)=>{ adate = new Date(2000, 0, 1); bdate = new Date(2000, 0, 1); if ('viewed_at' in a) {adate = new Date(a.viewed_at);} if ('viewed_at' in b) {bdate = new Date(b.viewed_at);} // 100000000: instead of just erasing the suggestions from previous week, // we just move them to the back of the queue acurweek = ((new Date()).getDate()-adate.getDate()>7)?0:100000000; bcurweek = ((new Date()).getDate()-bdate.getDate()>7)?0:100000000; aviews = 0; bviews = 0; if ('views' in a) {aviews = acurweek+a.views;} if ('views' in b) {bviews = bcurweek+b.views;} return bviews - aviews; }); new_recbooks = new_recbooks.slice(0,3); recommended_books = new_recbooks; } localStorage.setItem('PRETYPE_BOOKS_ANON', JSON.stringify({ previous_books: previous_books, recommended_books: recommended_books })); build_popup(); } } var whiletyping_search_object = null; var whiletyping_search = { books: [], curriculum: [], topics: [] } var single_whiletyping_ajax_promise = null; var whiletyping_database_initial_burst = 0; //number of consecutive calls, after 3 we start the 1 per 5 min calls function get_whiletyping_database() { //gets the database from the server. // 1. by validating against a local database value we confirm that the framework is working and // reduce the ammount of continuous calls produced by errors to 1 per 5 minutes. return localforage.getItem('whiletyping_last_attempt').then(function(value) { if ( value==null || (new Date()) - (new Date(value)) > 1000*60*5 || (whiletyping_database_initial_burst < 3) ) { localforage.setItem('whiletyping_last_attempt', (new Date()).getTime()); // 2. Make an ajax call to the server and get the search database. let databaseUrl = `/search/whiletype_database/`; let resp = single_whiletyping_ajax_promise; if (resp === null) { whiletyping_database_initial_burst = whiletyping_database_initial_burst + 1; single_whiletyping_ajax_promise = resp = new Promise((resolve, reject) => { $.ajax({ url: databaseUrl, type: 'POST', data:{csrfmiddlewaretoken: "GBuakaexwnvXSnKXvwcmAe2fh5nB22Q5Sps5WmVRl8nVh1d5Ol9e4l73AjfFBtxJ"}, success: function (data) { // 3. verify that the elements of the database exist and are arrays if ( ('books' in data) && ('curriculum' in data) && ('topics' in data) && Array.isArray(data.books) && Array.isArray(data.curriculum) && Array.isArray(data.topics)) { localforage.setItem('whiletyping_last_success', (new Date()).getTime()); localforage.setItem('whiletyping_database', data); resolve(data); } }, error: function (error) { console.log(error); resolve(null); }, complete: function (data) { single_whiletyping_ajax_promise = null; } }) }); } return resp; } return Promise.resolve(null); }).catch(function(err) { console.log(err); return Promise.resolve(null); }); } function get_whiletyping_search_object() { // gets the fuse objects that will be in charge of the search if (whiletyping_search_object){ return Promise.resolve(whiletyping_search_object); } database_promise = localforage.getItem('whiletyping_database').then(function(database) { return localforage.getItem('whiletyping_last_success').then(function(last_success) { if (database==null || (new Date()) - (new Date(last_success)) > 1000*60*60*24*30 || (new Date('2023-04-25T00:00:00')) - (new Date(last_success)) > 0) { // New database update return get_whiletyping_database().then(function(new_database) { if (new_database) { database = new_database; } return database; }); } else { return Promise.resolve(database); } }); }); return database_promise.then(function(database) { if (database) { const options = { isCaseSensitive: false, includeScore: true, shouldSort: true, // includeMatches: false, // findAllMatches: false, // minMatchCharLength: 1, // location: 0, threshold: 0.2, // distance: 100, // useExtendedSearch: false, ignoreLocation: true, // ignoreFieldNorm: false, // fieldNormWeight: 1, keys: [ "title" ] }; let curriculum_index={}; let topics_index={}; database.curriculum.forEach(c => curriculum_index[c.id]=c); database.topics.forEach(t => topics_index[t.id]=t); for (j=0; j

    Solutions
  • Textbooks
  • `); } function build_solutions() { if (Array.isArray(solution_search_result)) { const viewAllHTML = userSubscribed ? `View All` : ''; var solutions_section = $(`
  • Solutions ${viewAllHTML}
  • `); let questionUrl = "/questions/xxx/"; let askUrl = "/ask/question/xxx/"; solution_search_result.forEach((elem) => { let url = ('course' in elem)?askUrl:questionUrl; let solution_type = ('course' in elem)?'ask':'question'; let subtitle = ('course' in elem)?(elem.course??""):(elem.book ?? "")+"    "+(elem.chapter?"Chapter "+elem.chapter:""); solutions_section.find('#whiletyping-solutions').append(` ${elem.text} ${subtitle} `); }); $('#search-solution-options').empty(); if (Array.isArray(solution_search_result) && solution_search_result.length>0){ $('#search-solution-options').append(solutions_section); } MathJax.typesetPromise([document.getElementById('search-solution-options')]); } } function build_textbooks() { $('#search-pretype-options').empty(); $('#search-pretype-options').append($('#search-solution-options').html()); if (Array.isArray(textbook_search_result)) { var books_section = $(`
  • Textbooks View All
  • `); let searchUrl = "/books/xxx/"; textbook_search_result.forEach((elem) => { books_section.find('#whiletyping-books').append(` ${elem.title} ${ordinal(elem.edition)} ${elem.author} `); }); } if (Array.isArray(textbook_search_result) && textbook_search_result.length>0){ $('#search-pretype-options').append(books_section); } } function build_popup(first_time = false) { if ($('#search-text').val()=='') { build_pretype(); } else { solution_and_textbook_search(); } } var search_text_out = true; var search_popup_out = true; const is_login = false; const user_hash = null; function pretype_setup() { $('#search-text').focusin(function() { $('#search-popup').addClass('show'); resize_popup(); search_text_out = false; }); $( window ).resize(function() { resize_popup(); }); $('#search-text').focusout(() => { search_text_out = true; if (search_text_out && search_popup_out) { $('#search-popup').removeClass('show'); } }); $('#search-popup').mouseenter(() => { search_popup_out = false; }); $('#search-popup').mouseleave(() => { search_popup_out = true; if (search_text_out && search_popup_out) { $('#search-popup').removeClass('show'); } }); $('#search-text').on("keyup", delay(() => { build_popup(); }, 200)); build_popup(true); let prevbookUrl = `/search/pretype_books/`; let prebooks = null; try { prebooks = JSON.parse(localStorage.getItem('PRETYPE_BOOKS_'+(is_login?user_hash:'ANON'))); }catch(e) {} if (prebooks && 'previous_books' in prebooks && 'recommended_books' in prebooks) { if (is_login) { previous_books = prebooks.previous_books; recommended_books = prebooks.recommended_books; if (prebooks.time && new Date().getTime()-prebooks.time<1000*60*60*6) { build_popup(); return; } } else { anon_pretype(); return; } } $.ajax({ url: prevbookUrl, method: 'POST', data:{csrfmiddlewaretoken: "GBuakaexwnvXSnKXvwcmAe2fh5nB22Q5Sps5WmVRl8nVh1d5Ol9e4l73AjfFBtxJ"}, success: function(response){ previous_books = response.previous_books; recommended_books = response.recommended_books; if (is_login) { localStorage.setItem('PRETYPE_BOOKS_'+user_hash, JSON.stringify({ previous_books: previous_books, recommended_books: recommended_books, time: new Date().getTime() })); } build_popup(); }, error: function(response){ console.log(response); } }); } $( document ).ready(pretype_setup); $( document ).ready(function(){ $('#search-popup').on('click', '.search-view-item', function(e) { e.preventDefault(); let autoCompleteSearchViewUrl = `/search/autocomplete_search_view/`; let objectUrl = $(this).attr('href'); let selectedId = $(this).data('objid'); let searchResults = []; $("#whiletyping-solutions").find("a").each(function() { let is_selected = selectedId === $(this).data('objid'); searchResults.push({ objectId: $(this).data('objid'), contentType: $(this).data('contenttype'), category: $(this).data('category'), selected: is_selected }); }); $("#whiletyping-books").find("a").each(function() { let is_selected = selectedId === $(this).data('objid'); searchResults.push({ objectId: $(this).data('objid'), contentType: $(this).data('contenttype'), category: $(this).data('category'), selected: is_selected }); }); $.ajax({ url: autoCompleteSearchViewUrl, method: 'POST', data:{ csrfmiddlewaretoken: "GBuakaexwnvXSnKXvwcmAe2fh5nB22Q5Sps5WmVRl8nVh1d5Ol9e4l73AjfFBtxJ", query: $('#search-text').val(), searchObjects: JSON.stringify(searchResults) }, dataType: 'json', complete: function(data){ window.location.href = objectUrl; } }); }); });
    How many milliliters of concentrated hydrochloric acid solution ( 36.0 % HCl by mass, density =1.18  g / mL ) are required to produce 10.0  L of a solution that has a pH of 2.05 ? | Numerade (2024)

    FAQs

    How much concentrated HCl 37% HCl density 1.19 g mL is needed to prepare 100 mL of 10 g L HCl? ›

    Therefore, you will need 2.27 mL of the concentrated HCl then dilute it to 100 mL to prepare 100 mL of 10g/L. The answer is 2.27 mL.

    What is the density of solution concentrated HCl is 12.0 M and 36.0 HCl by mass? ›

    Expert-Verified Answer

    The density of the concentrated hydrochloric acid is (A) 1.22 g/mL. So, the correct answer is (A) 1.22 g/mL.

    How to prepare 10 HCl from 36.5 HCl solution? ›

    To make a 10% HCl solution, mix water, and Conc. hydrochloric acid (HCl) in a 10:1 ratio, which means that for every 100 mL of water, you'll need 10 mL of HCl to reach the necessary concentration. In a beaker, get the right amount of deionized (DI) water, and in another, get the right amount of HCl.

    What volume of concentrated HCl is required to make 1 l of 0.10 M HCl? ›

    (ii) What volume of concentrated HCl is required to make 1.0L of a 0.10M HCl? and V = volume. Thus the volume of concentrated HCl is 8.08L. Note: As we know that molarity is defined as the no.

    What is the density of 100 HCl in g mL? ›

    The specific gravity (density relative to the density of water) of hydrochloric acid solution is 1.18 g/mL.

    What is the density of 37 HCl in g mL? ›

    Concentrated HCl solution is 37.0% HCl and has a density of 1.19 g/mL.

    What is the density of 12M HCl in g mL? ›

    The density of 12 M hydrochloric acid solution is 1.18 g/mL and the density of water is 1.00 g/mL.

    What is the density of HCl at 35%? ›

    Physical Properties
    Physical state at 20 °CLiquidClear Colorless
    Melting point/ Freezing point [°C]-30 °C110 °C
    Density [g/cm3]1.2Soluble in water

    What is the density of concentrated HCl solution? ›

    Concentrated hydrochloric acid has 38% of HCl by weight with a density of 1.1885g per mL.

    What is the density of 36 HCl? ›

    Concentrated hydrochloric acid solution is 36.0% HCI by mass and has a density of 1.18 g/mL.

    How to calculate 36% HCl? ›

    1. 36% HCl by mass.
    2. 36g of HCl/100g of water.
    3. m = mole of solute/1kg of solvent.
    4. 36g/36.458 g/mole /64g of water.
    5. 0.99mole of HCL/64g of water.
    6. 64 x ? = 1000g so ? = 15.625.
    7. Multiply top and btm by 15.624 (in #5.
    8. 0.99mole of HCL x15.625/64g x 15.625 of water = 15.47moles/1kg.
    Nov 3, 2021

    What is the density of 36.5% HCl? ›

    36.5% HCl has density 1.20g/ml.

    What is the concentration of HCl 38% by mass? ›

    Concentrated HCl 38% by mass i.e 100gm of HCL soclution contains 38gm of HCl moles of HCl = given mass/molar mass = 38/36.5 Now density of solution = 1.19 g mL-1Since solution is 100gm.

    How to calculate the volume of concentrated hydrochloric acid? ›

    Concentrated hydrochloric acid has concentration of 12.19 mol/litre, The molar mass of HCl is 36.458 g/mol. 125 g is therefore (125/36.458) = 3.4286 moles. So the volume that would contain this number of moles is going to be (3.4286 / 12.19) = 0.28126 litres or 281.26 ml.

    How much HCl is in concentrated HCl? ›

    Hydrochloric acid is produced in solutions up to 38% HCl (concentrated grade). Higher concentrations up to just over 40% are chemically possible, but the evaporation rate is then so high that storage and handling require extra precautions, such as pressurization and cooling.

    What volume do you need to take from the concentrated HCl to prepare 100 mL of 0.1 M HCl solution? ›

    That is, 0.1 M x 100 ml = 12 M x V2. On solving for V2 = (0.1 x 100/12) = 0.83 ml. Hence, the volume of the concentrated HCl required for dilution = 0.83 ml. Use a graduated pipette to take 0.83 ml of Concentrated HCl into a clean glass beaker containing about 25 ml of distilled or deionised water.

    How do you calculate the concentration of 37 HCl? ›

    12M (37% HCL) = 12 moles/L = 12 x 36.5 = 438 g/L = 438 mg/ml.

    What is the molarity of 37% HCl AQ which has a density of 1.19 g mL? ›

    Example Calculation: If you have 37.0 grams of HCl in 100 grams of solution, you would have 37.0 g / 36.46 g/mol = 1.0147 moles of HCl. To find the volume of the solution, it would be 100 g / 1.19 g/mL = 84.03 mL or 0.08403 L. The molarity then is 1.0147 moles / 0.08403 L = 12.08 M.

    How to prepare 1M HCl in 100 mL? ›

    Determine molarity (M1) of starting, more concentrated solu tion. Add 8.26 mL of concentrated HCl to about 50 mL of distilled water, stir, then add water up to 100 mL.

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